64-48x^2=0

Solution for 64-48x^2=0 equation:

64-48x^2=0

a = -48; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-48)·64
Δ = 12288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12288}=\sqrt{4096*3}=\sqrt{4096}*\sqrt{3}=64\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{3}}{2*-48}=\frac{0-64\sqrt{3}}{-96}
=-\frac{64\sqrt{3}}{-96}
=-\frac{2\sqrt{3}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{3}}{2*-48}=\frac{0+64\sqrt{3}}{-96}
=\frac{64\sqrt{3}}{-96}
=\frac{2\sqrt{3}}{-3}
$